SIMON NIGERIA
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PHYSIC OBJ:
1-10: AACCCAABDC
11-20: BABAADAADD
21-30: DAAABBACDC
31-40: CDBDBACCAA
41-50: CCBADCCABD
(1a)
Projectile is a body undergoing
a motion under the combined
effect of horizontal and vertical
forces
(1b)
The horizontal components of
the velocity remains the same
because the body undergoes a
uniform motion
=========================
(2)
Angle of projection
(tita)=30degrees
velocity(u)=150m/s
At greatest height, v=0
t=Usin*tita/g
t=(150*sin30degrees)/10
=150*0.5/10
t=7.5s
=========================
(3)
Given original lenght
(Lo)=2.00m
radius(r)=1.0mm=1*10^-3m
Extension
(e)=25mm=2*10^-3m
Force(f)=10^3N
stress =force/area
Area(a)pie*R^2
=22/7*(10^-3)^2
3.142*10^16m^2
Stress=10^3/3.142*10^-6
=3.18*10^-1*10^3*10^6
=3.18*10^8Nm^-2
Strain=Extension/original
length
=25*10^-3/2
=1.25*10^-2
Young modulus
(Y)=3.18*10^8/1.25*10^-2
Y-2.54*10^10Nm^-2
=========================
(4)
-By wind
-By increasing the cup surface
area
-By reducing the temperature
=========================
(7a)
De brogile equation states that
landa=h/mv
where landa=wavelenght of
light
mv=p=momentum
h=planck's constant
(7b)
The equation is used to explain
the wave-nature of matter
=========================
(8ai)
Uniform acceleration occurs
when there is an equal
changein n velocity with equal
time interval no matter how
small the time interval may be
(8aii)
V=wr
V=linear velocity
w=angular velocity
r=radius
(8b)
R= resultant
R=root(F1^2 F2^2)
R=root(30^2 40^2)
R=root(2500)
R=50N
(8c)
This is done to increase the
surface friction in water
(8di)
Given;mass(m)=20kg
angle of inclineation
(tita)=30degrees
F=UR
F=Umgcos*tita
ma*sin*tita=Umg cos tita
U=tan*tita
U=tan30
U=0.51
(8dii)
Frictional force(Fr)
Fr=Umgcos*tita
Fr=0.51*20*10*c0s30
Fr=90.9N
(10ai)
Resonance ia a phenomenon
whereby a vibrating body sets
another bodies vibrating all
oscillating at d same neutal
frequency
(10aii)
(1)Radio-recieving circuit
(2)Sets of bob of pendulum
(10aiii)
Loudness is the sensation of
sound reaching d ear while
intensity is d ratio of d power
to d area
(10b)
Wavelenght & speed
(10d)
Given; focal lenght(f)=18.0m
Object distance(u)=90.0m
Image height(hi)=1.0m
(10di)
1/u+1/v=1/f
1/90+1/v=-1/18
1/v=-1/18-1/90
1/v=(-5-1)/90
1/v=-6/90
v=-90/6
=-15cm
(10dii)
v/u=hi/ho
15/90=1.0/h0
ho=90/15
=6cm
Lenght of shark is 6cm
(12a)
Nucleon number is the sum of
proton number and neutron
number
(12b)
95=c+a
95=c+2
c=95-2
c=93
(12bi)
Number of neutrons in
americium-241 is
237-93=144
(12ii)
a=2, b=4, c=93
(12ci)
Gamma ray is not deflected
because it has no charge
(12cii)
-It has the highest penetrating
power
-it has low ionizing power
(12d)
N/Nt=(1/2)^t1/2/T
1/32=(1/2)^(110/t1/2)
5=110/t1/2
5t1/2=110
t1/2=110/5
t1/2=22s
t1/2=0.693/landa
22=0.693/landa
landa=0.693/22
landa=0.0315
landa=0.0315 per year
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